Optimal. Leaf size=236 \[ -\frac{2 e^{3/2} \sqrt{\cos (c+d x)+1} \sqrt{a \sin (c+d x)+a} \tan ^{-1}\left (\frac{\sqrt{e} \sin (c+d x)}{\sqrt{\cos (c+d x)+1} \sqrt{e \cos (c+d x)}}\right )}{a^2 d (\sin (c+d x)+\cos (c+d x)+1)}+\frac{2 e^{3/2} \sqrt{\cos (c+d x)+1} \sqrt{a \sin (c+d x)+a} \sinh ^{-1}\left (\frac{\sqrt{e \cos (c+d x)}}{\sqrt{e}}\right )}{a^2 d (\sin (c+d x)+\cos (c+d x)+1)}-\frac{2 e \sqrt{a \sin (c+d x)+a} \sqrt{e \cos (c+d x)}}{a^2 d}-\frac{2 (e \cos (c+d x))^{5/2}}{d e (a \sin (c+d x)+a)^{3/2}} \]
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Rubi [A] time = 0.362183, antiderivative size = 236, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 8, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.296, Rules used = {2681, 2685, 2677, 2775, 203, 2833, 63, 215} \[ -\frac{2 e^{3/2} \sqrt{\cos (c+d x)+1} \sqrt{a \sin (c+d x)+a} \tan ^{-1}\left (\frac{\sqrt{e} \sin (c+d x)}{\sqrt{\cos (c+d x)+1} \sqrt{e \cos (c+d x)}}\right )}{a^2 d (\sin (c+d x)+\cos (c+d x)+1)}+\frac{2 e^{3/2} \sqrt{\cos (c+d x)+1} \sqrt{a \sin (c+d x)+a} \sinh ^{-1}\left (\frac{\sqrt{e \cos (c+d x)}}{\sqrt{e}}\right )}{a^2 d (\sin (c+d x)+\cos (c+d x)+1)}-\frac{2 e \sqrt{a \sin (c+d x)+a} \sqrt{e \cos (c+d x)}}{a^2 d}-\frac{2 (e \cos (c+d x))^{5/2}}{d e (a \sin (c+d x)+a)^{3/2}} \]
Antiderivative was successfully verified.
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Rule 2681
Rule 2685
Rule 2677
Rule 2775
Rule 203
Rule 2833
Rule 63
Rule 215
Rubi steps
\begin{align*} \int \frac{(e \cos (c+d x))^{3/2}}{(a+a \sin (c+d x))^{3/2}} \, dx &=-\frac{2 (e \cos (c+d x))^{5/2}}{d e (a+a \sin (c+d x))^{3/2}}-\frac{2 \int \frac{(e \cos (c+d x))^{3/2}}{\sqrt{a+a \sin (c+d x)}} \, dx}{a}\\ &=-\frac{2 (e \cos (c+d x))^{5/2}}{d e (a+a \sin (c+d x))^{3/2}}-\frac{2 e \sqrt{e \cos (c+d x)} \sqrt{a+a \sin (c+d x)}}{a^2 d}-\frac{e^2 \int \frac{\sqrt{a+a \sin (c+d x)}}{\sqrt{e \cos (c+d x)}} \, dx}{a^2}\\ &=-\frac{2 (e \cos (c+d x))^{5/2}}{d e (a+a \sin (c+d x))^{3/2}}-\frac{2 e \sqrt{e \cos (c+d x)} \sqrt{a+a \sin (c+d x)}}{a^2 d}-\frac{\left (e^2 \sqrt{1+\cos (c+d x)} \sqrt{a+a \sin (c+d x)}\right ) \int \frac{\sqrt{1+\cos (c+d x)}}{\sqrt{e \cos (c+d x)}} \, dx}{a (a+a \cos (c+d x)+a \sin (c+d x))}-\frac{\left (e^2 \sqrt{1+\cos (c+d x)} \sqrt{a+a \sin (c+d x)}\right ) \int \frac{\sin (c+d x)}{\sqrt{e \cos (c+d x)} \sqrt{1+\cos (c+d x)}} \, dx}{a (a+a \cos (c+d x)+a \sin (c+d x))}\\ &=-\frac{2 (e \cos (c+d x))^{5/2}}{d e (a+a \sin (c+d x))^{3/2}}-\frac{2 e \sqrt{e \cos (c+d x)} \sqrt{a+a \sin (c+d x)}}{a^2 d}+\frac{\left (e^2 \sqrt{1+\cos (c+d x)} \sqrt{a+a \sin (c+d x)}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{e x} \sqrt{1+x}} \, dx,x,\cos (c+d x)\right )}{a d (a+a \cos (c+d x)+a \sin (c+d x))}+\frac{\left (2 e^2 \sqrt{1+\cos (c+d x)} \sqrt{a+a \sin (c+d x)}\right ) \operatorname{Subst}\left (\int \frac{1}{1+e x^2} \, dx,x,-\frac{\sin (c+d x)}{\sqrt{e \cos (c+d x)} \sqrt{1+\cos (c+d x)}}\right )}{a d (a+a \cos (c+d x)+a \sin (c+d x))}\\ &=-\frac{2 (e \cos (c+d x))^{5/2}}{d e (a+a \sin (c+d x))^{3/2}}-\frac{2 e \sqrt{e \cos (c+d x)} \sqrt{a+a \sin (c+d x)}}{a^2 d}-\frac{2 e^{3/2} \tan ^{-1}\left (\frac{\sqrt{e} \sin (c+d x)}{\sqrt{e \cos (c+d x)} \sqrt{1+\cos (c+d x)}}\right ) \sqrt{1+\cos (c+d x)} \sqrt{a+a \sin (c+d x)}}{d \left (a^2+a^2 \cos (c+d x)+a^2 \sin (c+d x)\right )}+\frac{\left (2 e \sqrt{1+\cos (c+d x)} \sqrt{a+a \sin (c+d x)}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{1+\frac{x^2}{e}}} \, dx,x,\sqrt{e \cos (c+d x)}\right )}{a d (a+a \cos (c+d x)+a \sin (c+d x))}\\ &=-\frac{2 (e \cos (c+d x))^{5/2}}{d e (a+a \sin (c+d x))^{3/2}}-\frac{2 e \sqrt{e \cos (c+d x)} \sqrt{a+a \sin (c+d x)}}{a^2 d}+\frac{2 e^{3/2} \sinh ^{-1}\left (\frac{\sqrt{e \cos (c+d x)}}{\sqrt{e}}\right ) \sqrt{1+\cos (c+d x)} \sqrt{a+a \sin (c+d x)}}{d \left (a^2+a^2 \cos (c+d x)+a^2 \sin (c+d x)\right )}-\frac{2 e^{3/2} \tan ^{-1}\left (\frac{\sqrt{e} \sin (c+d x)}{\sqrt{e \cos (c+d x)} \sqrt{1+\cos (c+d x)}}\right ) \sqrt{1+\cos (c+d x)} \sqrt{a+a \sin (c+d x)}}{d \left (a^2+a^2 \cos (c+d x)+a^2 \sin (c+d x)\right )}\\ \end{align*}
Mathematica [C] time = 0.122615, size = 80, normalized size = 0.34 \[ -\frac{2^{3/4} \sqrt{a (\sin (c+d x)+1)} (e \cos (c+d x))^{5/2} \, _2F_1\left (\frac{5}{4},\frac{5}{4};\frac{9}{4};\frac{1}{2} (1-\sin (c+d x))\right )}{5 a^2 d e (\sin (c+d x)+1)^{7/4}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.101, size = 321, normalized size = 1.4 \begin{align*} -2\,{\frac{ \left ( e\cos \left ( dx+c \right ) \right ) ^{3/2} \left ( -1+\cos \left ( dx+c \right ) \right ) }{d\sin \left ( dx+c \right ) \left ( a \left ( 1+\sin \left ( dx+c \right ) \right ) \right ) ^{3/2} \left ( -1+\cos \left ( dx+c \right ) +\sin \left ( dx+c \right ) \right ) } \left ( \sqrt{2}\arctan \left ( 1/2\,\sqrt{2}\sqrt{-2\,{\frac{\cos \left ( dx+c \right ) }{1+\cos \left ( dx+c \right ) }}} \right ) \sin \left ( dx+c \right ) -\sqrt{2}{\it Artanh} \left ( 1/2\,{\frac{\sqrt{2}\sin \left ( dx+c \right ) }{\cos \left ( dx+c \right ) }\sqrt{-2\,{\frac{\cos \left ( dx+c \right ) }{1+\cos \left ( dx+c \right ) }}}} \right ) \sin \left ( dx+c \right ) -2\,\sqrt{-2\,{\frac{\cos \left ( dx+c \right ) }{1+\cos \left ( dx+c \right ) }}}\sin \left ( dx+c \right ) -2\,\cos \left ( dx+c \right ) \sqrt{-2\,{\frac{\cos \left ( dx+c \right ) }{1+\cos \left ( dx+c \right ) }}}+\sqrt{2}\arctan \left ( 1/2\,\sqrt{2}\sqrt{-2\,{\frac{\cos \left ( dx+c \right ) }{1+\cos \left ( dx+c \right ) }}} \right ) -\sqrt{2}{\it Artanh} \left ( 1/2\,{\frac{\sqrt{2}\sin \left ( dx+c \right ) }{\cos \left ( dx+c \right ) }\sqrt{-2\,{\frac{\cos \left ( dx+c \right ) }{1+\cos \left ( dx+c \right ) }}}} \right ) -2\,\sqrt{-2\,{\frac{\cos \left ( dx+c \right ) }{1+\cos \left ( dx+c \right ) }}} \right ){\frac{1}{\sqrt{-2\,{\frac{\cos \left ( dx+c \right ) }{1+\cos \left ( dx+c \right ) }}}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (e \cos \left (d x + c\right )\right )^{\frac{3}{2}}}{{\left (a \sin \left (d x + c\right ) + a\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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